abbr. colloq. body odour.
... diamond Diagonal diamonds intersect atpoint OBy theproperty oftheparallelogram AO = OC , thenBO .isthemedian ΔABC And since thetriangle ABC isisosceles , bytheproperties .ofthemedian ofanisosceles ... ... since thetriangle ABC isisosceles , bytheproperties .ofthemedian ofanisosceles triangle conducted tothe.base , BO isalso aheight andabisector Hence thestraight line BO ⊥ AC and ∠ ABO = CBO ... (Planometry)
... F The transformation of symmetry with respect to the point O. takes them to the points A `and B` AO = OA `,.BO = OB ` - by construction ). Consequently , AB = A`B`, which means symmetry with respect to. the point O is motion ... (Planometry)
... through the center . of the circle Connect point A with the center of the circle with. point O Δ ABO is isosceles (BO = AO as radii ). Therefore , ∠OBA = ∠OAB The external angle at the vertex O, the angle ... (Planometry)
... of equality . of triangles (∠ AOB = BOC , by condition , AO = OC - by the.property of the parallelogram diagonals , BO is common ). Therefore , AB = BC By the property of the opposite sides of the parallelogram . AB ... (Planometry)
... solution of.system can also be represented as ) ) The solution will. obviously be the only one Bo all such cases Examining the rank of the matrix , it is possible to. prove that if the solution of the system of equations ... (Digital image processing)
... . difficult or inaccessible to the child , the first syllable is.saved in the word , not the stressed one , for example : bo . - “hurts ”, mo - “milk ”, etc In mastering the syllable structure of words one ... (Psycholinguistics)
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